Question

Identify all factors of the expression 18x^2-9x-5

Answer 1

factors of
`f(x) = 18x^2-9x-5` are
`3x+1` and
`6x-5` .

Explanation:

Here we have , to identify all factors of this expression . let's find out :

Expression :
`f(x) = 18x^2-9x-5`

⇒
`f(x) = 18x^2-9x-5`

Now , -9x can be written as :

⇒
`-9x=-15x+6x`

Putting this value

⇒
`f(x) = 18x^2-15x+6x-5`

Taking out common terms we get

⇒
`f(x) = 3x(6x-5)+6x-5`

⇒
`f(x) = 3x(6x-5)+1(6x-5)`

⇒
`f(x) = (3x+1)(6x-5)`

Therefore , factors of
`f(x) = 18x^2-9x-5` are
`3x+1` and
`6x-5` .