Question

A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . If the charge is 0.030 m from the source of the electric field, what is the electric potential energy of the charge?

Answer 1

The electrical potential energy is 0.027 Joules.

Explanation:

The values from the question are

charge (q) =
`4.5 * 10^(-5) C`

Electric Field strength (E) =
`2.0 * 10^(4) N/C`

Distance from source (d) = 0.030 m

Now the formula for the electrical potential energy (U) is given by

`U = q * E * d`

So now insert the values to find the answer

`U = 4.5 * 10^(-5) C * 2.0 * 10^(4) N/C * 0.030 m`

On further solving

`U = 0.027 J`