Question

A 0.0997 mol sample of O2 has a pressure of 0.692 atm and a temperature of 333k. What is it’s volume

Answer 1

The volume is 4,391 L

Step-by-step explanation:

We use the formula PV=nRT:

V= (nRT)/P

V=(0,0997 mol x 0,082 l atm/ K mol x 333K) /0,692 atm

V=4, 390980968 L