Question

A line passes through (1,6) and (3,2). What is the equation of the line?

Answer 1

y = -2x + 8

Explanation:

The equation of a line

y = mx + c

y - intercept point y

m - slope of the line

x - Intercept point x

c - intercept of the line

Step 1: find the slope

m = y2 - y1 / x2 - x1

Given two points

( 1 , 6) ( 3 ,2)

x1 = 1

y1 = 6

x2 = 3

y2 = 2

m = 2 - 6 / 3 - 1

m = -4/2

m = -2

y = -2x + c

Step 2: sub any of the two points given into the equation

y = -2x + c

( 3 ,2)

x = 3

y = 2

2 = -2(3) + c

2 = -6 + c

2 + 6 = c

c = 8

Step 3: sub c into the equation

y = -2x + c

y = -2x + 8

The equation of the line is

y = -2x + 8