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Trig. QR = 15 ; PR = 28 ; PQ = 15, Cos __?__ = 15 / 28 I think its, cos= adjacent/hypotenuse, = QR/PR,=36/59. just want assurance

Trig. QR = 15 ; PR = 28 ; PQ = 15, Cos __?__ = 15 / 28 I think its, cos= adjacent/hypotenuse, = QR/PR,=36/59. just want assurance
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2 votes
Trig.

QR = 15 ; PR = 28 ; PQ = 15, Cos __?__ = 15 / 28
I think its, cos= adjacent/hypotenuse, = QR/PR,=36/59. just want assurance

asked
User Alexsouye
by
8.4k points

1 Answer

0 votes

Answer:

The ratio is correct

Explanation:

cos(Q) = adjacent /hypotenuse

= QR/PR

= 15/28

answered
User Jpsimons
by
7.6k points
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