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An airplane maintained an angle of climb of 72 degrees for a distance of 842 feet. What height did the airplane gain during this climb (to the nearest tenth)

asked
User AFract
by
7.4k points

2 Answers

6 votes

Answer:

800.8

Explanation:

Let, the height be h.

Then, sin72 = h/842

h = sin72 * 842

= 800.7895 = 800.8

[please inform if I'm wrong]

answered
User Martin Schimak
by
8.6k points
2 votes

Answer: the height gained by the airplane is 2591.4 ft

Explanation:

The airplane forms a right angle triangle with the ground. The height of the airplane above the ground represents the opposite side of the right angle triangle. The horizontal distance travelled by the airplane represents the adjacent side of the right angle triangle.

The line of movement of the airplane while maintaining the angle of climb of 72° represents the hypotenuse. To determine the height, h that the airplane gained during this climb, we would apply the tangent trigonometric ratio.

Tan θ, = opposite side/adjacent side. Therefore,

Tan 72 = h/842 =

h = 842tan72 = 842 × 3.0777

h = 2591.4 feet

answered
User Memoselyk
by
8.5k points
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