Question

Find the length of the third side. If necessary, round to the nearest tenth

Answer 1

`\qquad\qquad\huge\underline{{\sf Answer}}♨`

Let's use Pythagoras theorem !

`\qquad \sf  \dashrightarrow \:h {}^(2) = p {}^(2) + b {}^(2)`

where,

• h = hypotenuse = unknown

• b = base = 11

• p = perpendicular = 12

`\qquad \tt\dashrightarrow \:h {}^(2) = 12{}^(2) + 11 {}^(2)`

`\qquad \tt\dashrightarrow \:h {}^(2) = 144{}^{} + 121`

`\qquad \tt\dashrightarrow \:h {}^(2) = 265`

`\qquad \tt\dashrightarrow \:h {}^{} = √(265)`

`\qquad \tt\dashrightarrow \:h {}^{} \approx16.3`

Answer 2

for this equation we just use pythagorean theorem.

11^2+12^2=x^2
121+144=x^2
265=x^2
x=16.3