Answer:
6.83L
Step-by-step explanation:
It has been proven that 1mole of any gas occupy 22.4L at stp. This also indicates that 1mole of O2 occupies 22.4L at stp.
Now if 1mole O2 occupies 22.4L at stp, then 0.305 mole of O2 will occupy = 0.305 x 22.4 = 6.83L at stp.
Therefore, 0.305 mole of O2 occupies 6.83L at stp.