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If f ( 1 ) = 2 f(1)=2 and f ( n ) = f ( n − 1 ) 2 − 5 f(n)=f(n−1) 2 −5 then find the value of f ( 4 ) f(4).
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If f ( 1 ) = 2 f(1)=2 and f ( n ) = f ( n − 1 ) 2 − 5 f(n)=f(n−1) 2 −5 then find the value of f ( 4 ) f(4).
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Apr 25, 2023
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If f ( 1 ) = 2 f(1)=2 and f ( n ) = f ( n − 1 ) 2 − 5 f(n)=f(n−1) 2 −5 then find the value of f ( 4 ) f(4).
Mathematics
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Clemensp
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Answer:
f(4) = 11
Explanation:
Given
:
base function ⇒ f(n) = f(n - 1)² - 5
f(1) = 2
Solving
:
f(2) = f(1)² - 5
f(2) = 2² - 5 = 4 - 5 =
-1
f(3) = f(2)² - 5
f(3) = (-1)² - 5 = 1 - 5 =
-4
f(4) = f(3)² - 5
f(4) = (-4)² - 5
f(4) = 16 - 5 =
11
Fearghal
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Apr 25, 2023
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Fearghal
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5
votes
so
f(4) = 11
Hope that helps!
Rakesh Kashyap
answered
Apr 29, 2023
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Rakesh Kashyap
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