Question

Write (1/13)^2=1/169 in logarithmic form

Answer 1

`\log_(1/13)(1/169)=2`

Explanation:

The exponential expression b^a=c is equivalent to the log expression ...

`\log_b{(c)}=a`

Filling in a=2, b=1/13, c=1/169 you get the logarithmic form ...

`\boxed{\log_(1/13)(1/169)=2}`