asked 45.2k views
3 votes
30g of naoh is dissolved in 1.5 liter solution the active mass of naoh is?

asked
User Jgiles
by
7.7k points

1 Answer

3 votes

Answer:

0.5mol/L

Step-by-step explanation:

First, let us calculate the number of mole NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the question = 30g

Number of mole = Mass /Molar Mass

Number of mole = 30/40 = 0.75mol

Volume = 1.5L

Active mass = mole/Volume

Active mass = 0.75mol/1.5L

Active mass = 0.5mol/L

answered
User Josefx
by
7.9k points
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