Question

The sum of the squares of the odd integers between 0 and 100.

Using summation notation

Answer 1

166,649.

Explanation:

49

∑ (2n + 1)^2 = 4∑n^2 + 4∑n + 49

0

= (4/6)n(n +1)(2n + 1) + 4/2 n(n + 1) + 49

= 2/3 * 49* 50 *99 + 2*49*50 + 49

= 161700 + 4900 + 49

= 166649