Question

Does anyone know this??

Answer 1

`sinA=(12)/(37) \\\\cosA=(35)/(37)\\\\ tanA=(12)/(35)`

Explanation:

In the given triangle we have to find the ratios of
`sinA` ,
`cosA` and
`tan A`

Given:

`Perpendicular= 12\\\\ Base= 35\\\\ Hypotenuse=37`

Ratio of
`sinA`

`sinA= (Perpendicular)/(Hypotenuse) \\\\sinA= (12)/(37)\\`

Ratio of
`cosA`

`cos A=(Base)/(Hypotenuse)\\\\ cosA=(35)/(37)`

Ratio of
`tan A`

`tanA=(Perpendicular)/(Base) \\\\tanA=(12)/(35)`