Question

Guys can someone pls help me out with this... tysm!!

Answer 1

It is yes for ordered pairs 1 and 4. It is no for ordered pairs 2 and 3.

Explanation:

Step 1:

The given equations are multiples of each other so they have an infinite number of solutions.

So we need to substitute the values of x and y in the equations to determine which ordered pairs are solutions to the given equations.

Step 2:

When (x, y) = (7, 11),
`y =2x-3, 11 = 2(7)-3 = 14 -3 =11.`

`6x-3y=9, 6(7) - 3(11) = 42 - 33 = 9.`

So the first ordered pair is a solution to the given system of equations.

When (x, y) = (4, -5),
`y =2x-3, -5= 2(4)-3 = 8 -3 =5.`

-5 ≠ 5,

So the second ordered pair is not a solution.

Step 3:

When (x, y) = (-1, 8),
`y=2x-3, 8 = 2(-1)-3 = -2-3 =-5.`

8 ≠ -5,

So the third ordered pair is not a solution.

When (x, y) = (0, -3),
`y =2x-3, -3 = 2(0)-3 = 0 -3 =-3.`

`6x-3y=9, 6(0) - 3(-3) = 0 + 9 = 9.`

So the fourth ordered pair is a solution to the given system of equations.