Question

What is the value of x in the equation ?StartFraction 2 Over 3 EndFraction left-parenthesis StartFraction one-half EndFraction. x lus 12 right-parenthesis equals left-parenthesis StartFraction one-half EndFraction left-parenthesis StartFraction one-third EndFractin x plus 14 right-parenthesis minus 3.StartFraction one-half End

Answer 1

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Explanation:

Answer 2

The value of x in the equation
`(2)/(3)((1)/(2)x + 12) = ((1)/(2)((1)/(3)x + 14) - 3\frac12)` is x = -27

How to determine the value of x in the equation

From the question, we have the following parameters that can be used in our computation:

`(2)/(3)((1)/(2)x + 12) = ((1)/(2)((1)/(3)x + 14) - 3\frac12)`

Express fractions as improper fractions

So, we have

`(2)/(3)((1)/(2)x + 12) = ((1)/(2)((1)/(3)x + 14) - \frac72)`

Open the brackets

`(1)/(3)x + 8 = (1)/(6)x + 7 - \frac72`

Multiply through by 6

2x + 48 = x + 42 - 21

This gives

2x - x = 42 - 21 - 48

Evaluate

x = -27

Hence, the value of x in the equation is x = -27

Question

What is the value of x in the equation?

`(2)/(3)((1)/(2)x + 12) = ((1)/(2)((1)/(3)x + 14) - 3\frac12)`