Question

Polygon ABCDE is an irregular pentagon. Find the perimeter of the polygon. Round to the nearest tenth. Round to give final answer only.

Answer 1

12.9

Explanation:

AB =
`\sqrt{2^(2)+3^(2) }` =
`√(13)`

BC =
`\sqrt{2^(2)+2^(2) }` =
`2√(2)`

CD =
`\sqrt{1^(2)+2^(2) }` =
`√(5)`

DE = 3

EA =
`\sqrt{1^(2) + 2^(2) }` =
`√(5)`

The sum of all of these (in decimal form) is (approx.) 12.9

Answer 2

13.9 units

Explanation:

AB = sqrt(2² + 3²) = sqrt(13)

BC = sqrt(2² + 2² = sqrt(8)

CD = sqrt(1² + 2²) = sqrt(5)

DE = 3

EA = sqrt(1² + 2²) = sqrt(5)

Add all these:

13.9 units