Question

Farmer Fran has 38 barnyard animals consisting of only chickens and goats. If these animals have 116 legs how many of each type of animal are there?

Answer 1

chickens is represented by C, and the number of goats is G.

C=18

G=20

Total of Animals equation:

a)C+ G = 38

Total of legs equation (since chickens have 2 legs and goats have 4 ):

b)2C + 4 G =116

If we multiply a) by 2 and subtract a) from b).

2C + 4 G =116

-

2C + 2 G =76

_________

2G = 40

Solving for G:

G = 40/2

G= 20

Replacing the value of G on any equation:

a) C+ (20) =38

Solving for C

C =38-20

C=18

There are 20 goats and 18 chickens.

Answer 2

Answer: There are 20 goats and 18 chikens.

Explanation:

Hi, to answer this question we have to write a system of equations:

If the number of chickens is represented by C, and the number of goats is G.

Total of Animals equation:

a)C+ G = 38

Total of legs equation (since chickens have 2 legs and goats have 4 ):

b)2C + 4 G =116

If we multiply a) by 2 and subtract a) from b).

2C + 4 G =116

-

2C + 2 G =76

_________

2G = 40

• Solving for G:

G = 40/2

G= 20

Replacing the value of G on any equation:

a) C+ (20) =38

• Solving for C

C =38-20

C=18

There are 20 goats and 18 chickens.