Question

H(y)=9/5 • 2y at y=-2

Answer 1

`H( - 2) = - 7 (1)/(5)`

Explanation:

We want to evaluate the equation

`H(y) = (9)/(5) * 2y`

at y=-2

We just have to substitute to obtain;

`H( - 2) = (9)/(5) * 2 * - 2`

We now multiply to get:

`H( - 2) = (9)/(5) * - 4`

This is the same as:

`H( - 2) = (9)/(5) * ( - 4)/(1)`

We multiply the numerators separately and denominators separately to get:

`H( - 2) = (9 * - 4)/(5 * 1)`

`H( - 2) = ( - 36)/(5)`

This implies that

`H( - 2) = - 7 (1)/(5)`