Question

What is the magnitude of the electric field at a distance 60 cm from the center of the sphere? The radius of the sphere 30 cm, the charge on the sphere is 1.56 × 10−5 C and the permittivity of a vacuum is 8.8542 × 10−12 C 2 /N · m2 . Answer in units of N/C.

Answer 1

Step-by-step explanation:

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Answer 2

`3.9*10^(5)N/C`

Step-by-step explanation:

from the expression for determing the magnetic field strength

`E=(q)/(4\pi e_(0)d^2 )\\`

since the charge is given as

`q=1.56*10^(-5)c\\`

and the distance is

d=60cm=0.6m

We can calculate the constant k

`K=(1)/(4\pi e_(0))\\ K=(1)/(4\pi *8.8542*10^(-12))\\k=8.98*10^(9)\\`

if we substitute values, we arrive at

`E=(8.98*10^9 *1.56*10^(-5))/(0.6^2) \\E=389133.33\\E=3.9*10^(5)N/C`