A velocity selector in a mass spectrometer uses a 0.150 T magnetic field. (a) What electric field strength (in volts per meter) is needed to select a speed of 4.40 ✕ 106 m/s? V/…

Question

asked Sep 23, 2021 145k views

1 Answer

Ribram · Answer 1 · 2021-09-29T23:24:55+0000

Answer:

The electric field strength is
$6.6*10^(5)\ V/m$

Step-by-step explanation:

Given that,

Magnetic field = 0.150 T

Speed
$v= 4.40*10^(6)\ m/s$

We need to calculate the electric field strength

Using formula of velocity

v=(E)/(B)

E=v* B

Where, v = speed

B = magnetic field

Put the value into the formula

E=4.40*10^(6)*0.150

$E=660000\ V/m$

$E=6.6*10^(5)\ V/m$

Hence, The electric field strength is
$6.6*10^(5)\ V/m$