Question

In one experiment, the reaction of 1.00 mercury and an excess of sulfur yielded 1.16g of a sulfide of mercury

What mass remained unreacted in the second experiment?

Answer 1

Answer and Explanation:

Mercury combines with sulfur as follows -

Hg + S = HgS

Hg = 200,59

S = 32,066 Therefore 1.58 g of Hg will react with -

1.58 multiply with 32,066 divide by 200,96 of sulfur.

= 0.25211 g S

This will form 1.58 + 0.25211 g HgS = 1.83211 g HgS

The amount of S remaining = 1.10 - 0.25211 = 0.84789 g