A man pushes with a force of 300 N on a bookcase of mass 75 kg. The coefficient of static friction between the bookcase and the floor is 0.9. Because of friction, the bookcase d…

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asked Jul 15, 2021 159k views

2 Answers

Hustlion · Answer 1 · 2021-07-16T01:45:20+0000

The force of friction on the bookcase is 662 N.

The force of friction on the bookcase can be found using the equation:

friction force = coefficient of static friction * normal force

The normal force is equal to the weight of the bookcase, which can be found using the equation:

weight = mass * gravity

Substituting the given values:

weight = 75 kg * 9.8 m/s^2

The coefficient of static friction is 0.9, so the force of friction can be calculated as:

friction force = 0.9 * weight

Substituting the weight value:

friction force = 0.9 * (75 kg * 9.8 m/s^2)

Solving this equation gives an answer of 662 N.