Question

To throw the discus, the thrower holds it with a fully outstretched arm. Starting from rest, he begins to turn with a constant angular acceleration, releasing the discus after making one complete revolution. The diameter of the circle in which the discus moves is about 1.7 m.

Answer 1

Incomplete question.The complete question is here

To throw the discus, the thrower holds it with a fully outstretched arm. Starting from rest, he begins to turn with a constant angular acceleration, releasing the discus after making one complete revolution. The diameter of the circle in which the discus moves is about 1.7 m.If the thrower takes 1.0 s to complete one revolution, starting from rest, what will be the speed of the discus at release?

Answer:

`v=10.676m/s`

Step-by-step explanation:

Radius r=1.7m/2 =0.85 m

The angular displacement in time t is:

θ=1/2αt²

where α is angular acceleration

Given

θ=2π

t=1.0s

So

α=2θ/t²

`\alpha =(2*2\pi )/((1.0s)^(2) ) \\\alpha =4\pi rad/s^(2)`

Angular speed after 1.0s is:

`w=\alpha t=4\pi rad/s^(2) *1.0s\\w=4\pi rad/s`

Speed of discus is given by:

`v=rw\\v=(0.85)(4\pi )\\v=10.676m/s`