Question

Q(x)=

3x
2
+x
9

6x
5
−2
​
q, left parenthesis, x, right parenthesis, equals, start fraction, 6, x, start superscript, 5, end superscript, minus, 2, divided by, 3, x, squared, plus, x, start superscript, 9, end superscript, end fraction
Find the horizontal asymptote of
q
qq.

Answer 1

q = 0

Explanation:

The ratio of highest-degree terms is (6x^5)/(x^9) = 6/x^4. This approaches zero when x gets large, either positive or negative.

The horizontal asymptote is q = 0.