Question

A POSITIVE POINT CHARGE q1 creates an electric field of magnitude E1 at a spot located at a distance r1 from the charge. The charge is replaced by another positive point charge q2, which creates a field of magnitude E2=E1 at a distance of r2=2r1. How is q2 related to q1? (a)q2=2q1 (b)q2=1/2q1 (c) q2= 4q1 (d)q2 =1/4 q1 (e) q2= sqroot 2 q1

Answer 1

q₂ = 4 q₁

Step-by-step explanation:

We know ,electric fled due to a charge q is given as

`E=K(q)/(r^2)`

q=Charge

r=Distance

K=Constant

E=Electric field

Electric field due to charge q₁

`E_1=K(q_1)/(r_1^2)`

Electric field due to charge q₂

`E_2=K(q_2)/(r_2^2)`

E₂ = E₁

r₂ = 2 r₁

`K(q_2)/(r_2^2)=K(q_1)/(r_1^2)`

`(q_2)/((2r_1)^2)=(q_1)/(r_1^2)`

`(q_2)/(4r_1^2)=(q_1)/(r_1^2)`

q₂ = 4 q₁

Therefore the option C is correct.