Question

Square root 3a-2 = square root a/b (make b the subject)

Answer 1

b = a/(3a-2)

Explanation:

(3a-2)^½ = (a/b)½

Square both sides

3a - 2 = a/b

Reciprocate both sides

1/(3a-2) = b/a

b = a/(3a-2)

Answer 2

b =
`(a)/(3a-2)`

Explanation:

Given

`√(3a-2)` =
`\sqrt{(a)/(b) }`

Clear the radicals by squaring both sides

(
`√(3a-2)` )² = (
`\sqrt{(a)/(b) }` )², that is

3a - 2 =
`(a)/(b)` ( multiply both sides by b )

b(3a - 2) = a ← divide both sides by (3a - 2)

b =
`(a)/(3a-2)`