Question

Given that events A and B are mutually exclusive, i.e., A?B = ? and P(A?B) =0, and that P(A)=0.7 and P(B)=0.2, find P(A or B).

(a) 0.14

(b) 0.9

(c) 0.5

(d) 0.76

(e)1.04

Answer 1

`P(A or B)= P(A \cup B) = 0.9`

Explanation:

given ,
`P(A)=0.7`
`P(B)=0.2`

`P(A or B) = P(A \cup B) =0`

since it is mutually exclusive event ,
`P(A and B)= P(A \cap B) =P(A?B) = 0`

`P(A \cup B) = P(A) + P(B) - P(A\cap B)`

`P(A \cup B) = 0.7 + 0.2 - 0`

`P(A \cup B) = 0.9`