What is the empirical formula of a compound composed of 28.7 g of potassium ( K ) and 5.87 g of oxygen ( O )? Insert subscripts as needed.

Question

asked Aug 27, 2021 5.7k views

1 Answer

MDT · Answer 1 · 2021-09-02T11:54:08+0000

Answer : The empirical formula for the given compound is
K_2O

Explanation :

Step 1: Converting the given masses into moles.

$\text{ Moles of }K=\frac{\text{ Mass of }K}{\text{ Molar mass of }K}=(28.7g)/(39g/mole)=0.736moles$

$\text{ Moles of }O=\frac{\text{ Mass of }O}{\text{ Molar mass of }O}=(5.87g)/(16g/mole)=0.367moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.367 moles.

For Potassium =
$(0.736)/(0.367)=2.00\approx 2$

For Oxygen =
(0.367)/(0.367)=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of K : O = 2 : 1

Hence, the empirical formula for the given compound is
K_2O