Question

A 440-Hz tuning fork is now used with a closed-end tube resonating column to determine the velocity of sound in a different gas than air. If the spacings between resonances are 1.10 m, what is the velocity of sound in this medium?

Answer 1

Step-by-step explanation:

Given

frequency
`\\u =440\ Hz`

Spacing between the resonance is
`=1.10`

For one end closed resonance spacing is given by

Resonance spacing
`=(\lambda )/(4)`

`\lambda =4* 1.1`

`\lambda =4.4\ m`

and velocity is given by

`velocity=frequency* wavelength`

substituting the values we get

`v=440* 4.4`

`v=1936\ m/s`