Question

A wave has an amplitude of

0.0800 m and is moving 7.33 m/s.
One oscillator in the wave takes
0.115 s to go from the lowest point
in its motion to the highest point.
Find the frequency of the wave.
(Unit = Hz)​

Answer 1

0.230

Step-by-step explanation:

That's the answer, the one above isn't, I got this answer correct on acellus

Answer 2

The frequency of wave is 4.34 Hz.

Step-by-step explanation:

We know the relation:

λ =
`(v)/(f)` =
`v` ×
`T`........................................1

where,

λ= wavelength

v= velocity of wave

T= Period of wave

By the definition of period T, you are given that HALF of T is 0.115 s, so

T = 2 × (0.115 s)

= 0.23 s

Then ,

λ = v × T

= (7.33 m/s) × (0.23 s)

≅ 1.686 m

Now for frequency, return to equation 1,

`f` =
`(v)/( \lambda )`

=
`(7.33)/(1.686)`

= 4.34

The frequency of the wave is calculated as 4.34 Hz.