Question

Identify the zeros of the function f(x) =2x^2 − 2x + 13 using the Quadratic Formula. SHOW WORK PLEASE!! I NEED HELP!!

Answer 1

`x=\frac{1+5i} {2}` and
`x=\frac{1-5i} {2}`

Explanation:

we know that

The formula to solve a quadratic equation of the form

`ax^(2) +bx+c=0`

is equal to

`x=\frac{-b\pm\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`f(x)=2x^(2) -2x+13`

Equate the function to zero

`2x^(2) -2x+13=0`

so

`a=2\\b=-2\\c=13`

substitute in the formula

`x=\frac{-(-2)\pm\sqrt{-2^(2)-4(2)(13)}} {2(2)}`

`x=\frac{2\pm√(-100)} {4}`

Remember that

`i=√(-1)`

so

`x=\frac{2\pm10i} {4}`

Simplify

`x=\frac{1\pm5i} {2}`

therefore

`x=\frac{1+5i} {2}` and
`x=\frac{1-5i} {2}`