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When factored completely, the expression p^4−81 is equivalent to Question 2 options: (p2+9)(p2−9) (p2−9)(p2−9) (p2+9)(p+3)(p−3) (p+3)(p−3)(p+3)(p−3)

When factored completely, the expression p^4−81 is equivalent to Question 2 options: (p2+9)(p2−9) (p2−9)(p2−9) (p2+9)(p+3)(p−3) (p+3)(p−3)(p+3)(p−3)
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When factored completely, the expression p^4−81 is equivalent to

Question 2 options:

(p2+9)(p2−9)

(p2−9)(p2−9)

(p2+9)(p+3)(p−3)

(p+3)(p−3)(p+3)(p−3)

asked
User Stealth Rabbi
by
7.7k points

1 Answer

2 votes

Answer:

(p2+9)(p+3)(p-3)

Explanation:

(p^4-81) = (p2+9)(p2-9)

= (p2+9)(p+3)(p-3)

answered
User Pocheptsov
by
8.2k points
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