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P(x) = x^2-4x+4 tại x =2

P(x) = x^2-4x+4 tại x =2
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P(x) = x^2-4x+4 tại x =2

asked
User Nemanja Trifunovic
by
7.9k points

1 Answer

5 votes

If
P(x) = x^2-4x+4 and x =2

-->
P(2) = 2^2-4(2)+4=4-8+4=0

Hope that helps!

answered
User Vishal Sharma
by
8.0k points
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