Question

a projectile with mass m is fired with initial horizontal velocity vx from height h above level ground. which change would have resulted in a greater time of flight for the projectile?

Answer 1

Step-by-step explanation:

initial velocity in horizontal direction = vx

Height = h

Let the time of light is t.

Use second equation of motion in vertical direction

h = ut + 1/2 at²

h = 0 + 0.5 gt²

`t=\sqrt{(2h)/(g)}`

So, to increase the time of flight, we have to increase the value of height.

Answer 2

Step-by-step explanation:

We know that in a projectile motion time of flight

`t= \sqrt{(h)/(4.9) }`

So, we can notice that time of flight is dependent only on height from which the projectile is thrown. The more the height the more will be time of flight. So, if we increase the height the time of flight of the projectile will certainly increase.