Question

Solid cesium iodide has the same kind of crystal structure as CsCl which is pictured below: If the edge length of the unit cell is 456.2 pm, what is the density of CsI in g/cm3.

Answer 1

The question is incomplete, here is the complete question:

Solid cesium iodide has the same kind of crystal structure as CsCl which is pictured below: If the edge length of the unit cell is 456.2 pm, what is the density of CsI in
`g/cm^3`

The image is attached below.

Answer: The density of CsI is
`9.09g/cm^3`

Step-by-step explanation:

To calculate the density of metal, we use the equation:

`\rho=(Z* M)/(N_(A)* a^(3))`

where,

`\rho` = density

Z = number of atom in unit cell = 2 (BCC)

M = atomic mass of CsI = 259.8 g/mol

`N_(A)` = Avogadro's number =
`6.022* 10^(23)`

a = edge length of unit cell =
`456.2pm=456.2* 10^(-10)cm` (Conversion factor:
`1cm=10^(10)pm` )

Putting values in above equation, we get:

`\rho=(1* 259.8)/(6.022* 10^(23)* (456.2* 10^(-10))^3)\\\\\rho=9.09g/cm^3`

Hence, the density of CsI is
`9.09g/cm^3`