
Here, We have given 
- 2 squares , In which 1 square is enclosed within the another square and it arranged in a form that it forms 4 right angled triangle 
- The height and base of the given right angled triangles are 6 and 3 each. 
We know that, 
Area of triangle 

Subsitute the required values, 



Therefore, 
Area covered by 4 right angled triangles


Now, 
We have to find the area of the big square 
- The length of the side of the big square
  
We know that, 
Area of square

Subsitute the required values, 


Therefore, 
The total area of shaded region 
= Area of big square - Area covered by 4 right angled triangle 


Hence, The total area of shaded region is 45 .
Part 2 :-
Here, 
We have to find the area of non shaded region 
According to the question 
- Hypotenuse = The length of square 
Let the hypotenuse of the given right angled triangle be x 
Therefore, 
By using Pythagoras theorem, 
- This theorem states that the sum of the squares of the base and perpendicular height is equal to the square of hypotenuse. 
That is, 

Subsitute the required values 




That means, 
- The length of the small square = 6.7
We know that ,
Area of square 

Subsitute the required values, 


Therefore ,
Area of non shaded region 
= Area of big square - Area of small square 


Hence, The total area of non shaded region is 36.1 or 36  (approx) .
Part 3 :-
Here, we have to 
- find the total area of the figure 
Therefore, 
The total area of the figure 
= Non shaded region + Shaded region 


Hence, The total area of the given figure is 81 .