Question

How much energy in kilojoules is released when 23.4 g of ethanol vapor at 83.0 ∘C is cooled to -15.0 ∘C ?

Answer 1

Answer : The amount of in kilojoules released is, -5.53 kJ

Explanation :

Formula used :

`q=m* c* (T_(final)-T_(initial))`

where,

q = heat released = ?

c = specific heat of ethanol =
`2.41J/g^oC`

m = mass of ethanol = 23.4 g

`T_(final)` = final temperature =
`-15.0^oC`

`T_(initial)` = initial temperature =
`83.0^oC`

Now put all the given values in the above formula, we get:

`q=23.4g* 2.41J/g^oC* (-15.0-83.0)^oC`

`q=-5526.612J=-5.53* 10^3J=-5.53kJ`

Therefore, the amount of in kilojoules released is, -5.53 kJ