Question

What inequality is shown above?

A. Y<-1/3X+2
B. Y>-3X+2
C. Y>-1/3X+2
D. Y<-3X+6​

Answer 1

y = -1/3x + 2

Explanation:

Two points of the inequality

(0,2)

(3,1)

Gradient of the inequality

`(y_(2)-y_(1))/(x_(2)-x_(1))`

`(1-2)/(3-0)\\(-1)/(3)`

Substitute one of the points into y = -1/3x + c to find c

y = -1/3x + c at (0,2)

2 = -1/3(0) + c

2 = 0 + c

2 = c

y = -1/3x + c at (3,1)

1 = -1/3(3) + c

1 = -1 + c

1 + 1 = c

2 = c

y = -1/3x + c

Replace c with 2

y = -1/3x + 2