Question

in the function fx=a(x+2)(x-3)^b, a and b are bothj integer constants and b is positive, find the value of x for f(x)=0

Answer 1

f(x) = 0 , when x=(-2) and x=3

Explanation:

for a≠0 and b positive then for the function

f(x) = a*(x+2)*(x-3)ᵇ

f(x) = 0 when

1) (x+2)=0 → x=(-2)

2) (x-3)=0 → x=-3

then for x=3 and x=(-2) , f(x)=0