Question

A pyramid has a horizontal square base of 12cm. the vertex of the pyramid is 7cm vertically above the base. calculate, correct to one decimal place:

(i) the length of the slant height

Answer 1

9.2 cm.

Explanation:

A pyramid has a horizontal square base of 12 cm. The vertex of the pyramid is 7 cm vertically above the base.

So, the height of the pyramid is 7 cm and half-length i.e. half base is equal to
`(12)/(2) = 6` cm.

Now, the slant height of a pyramid is the altitude of the side triangles.

Therefore, the length of the slant height will be equal to
`\sqrt{6^(2) + 7^(2)} = 9.219` cm ≈ 9.2 cm. (Answer)