Question

Please help!!!!!

What is the equation of the axis of symmetry for the parabola
y=2/3(x-2)^2-5

x=2/3
x=-2
x=2
x=-5

Answer 1

Axis of the symmetry is x=2.

Explanation:

Given :

Equation of a parabola in vertex form.

⇒
`y=(2)/(3)(x-2)^2 -5`

Note:

Axis of symmetry divides the parabola in two equal halves.

General vertex form y=a(x−h)^2+k

And the axis of symmetry (x)= h

Comparing our values with the vertex form.

We can say that.

⇒a=
`(2)/(3)`

⇒h=
`2` and

⇒k=
`-5`

Axis of symmetry is (x) = h=2

Axis of symmetry of the parabola is x = 2.

Option C is the right answer.