Question

Write a recursive formula for f(n) = -3 + 2 for n > = 1

Answer 1

`f(n) = f(n - 1) - 3`

Explanation:

Assuming the explicit formula is

`f(n) = - 3n + 2`

Then f(1)=-3+2=-1

f(2)=-6+2=-4

The common difference is -4--1=-3

Then the recursive formula is given as:

`f(n) = f(n - 1) + d`

`f(n) = f(n - 1) - 3`