Question

An urn contains 3 red, 8 yellow and 13 green balls; another urn contains 5 red, 7 yellow and 6 green balls. We pick one ball from each urn at random. Find the probability that both balls are of the same color.

Answer 1

The number of possible outcomes is 24×18.

The number of favorable outcomes are as follows: (3×5)+(8×7)+(13×6)

The probability is simply:

(3×5)+(8×7)+(13×6)/24×18=149/432

Explanation: