Question

Find the real solutions of the equation by graphing

-19x^3– 12x^2 – 16x = 0

A. -1.29
B. -1.29, 0.65
C. 0, 1.29, -0.65
D. 0, -1.29. 0.65

Answer 1

C. 0, 1.29, -0.65

Explanation:

The real solutions of the equation
`19x^3-12x^2-16x=0` is where the graph of
`y=19x^3-12x^2-16x` intersects the x-axis.

This means that we need to graph
`y=19x^3-12x^2-16x` using a graphing software.

From the graph shown in the attachment
`x=0`,
`x=1.29`, and
`x=-0.65` are the real solutions.

The correct choice is C