Question

The radius of the earth very nearly circular orbit around the sun is

1.50
⋅
10
11
m. What is the magnitude of the earth‘s velocity and centripetal acceleration as it travels around the sun?

Answer 1

given,

radius of earth,r = 1.5 x 10¹¹ m

Time,T = 365 days

= 365 x 24 x 3600 s

earth velocity,

`v=(2\pi r)/(T)`

`v=(2\pi (1.5* 10^(11)))/(365* 24* 3600)`

v = 3 x 10⁴ m/s

centripetal acceleration of the earth

`a = (v^2)/(r)`

`a = ((3* 10^4)^2)/(1.5* 10^(11))`

a = 6 x 10⁻³ m/s²