Question

Help pls wit algebra 2

Answer 1

C

Explanation:

If
`R_A=3R_B, T_A+T_B=12,` then

`R_A=3R_B\\ \\T_A=12-T_B`

Substitute them into the equation
`R_AT_A=360:`

`3R_B\cdot (12-T_B)=360\\ \\36R_B-3R_BT_B=360\\ \\12R_B-R_BT_B=120`

Given
`R_BT_B=60,` then

`12R_B-60=120\\ \\12R_B=120+60\\ \\12R_B=180\\ \\R_B=15\\ \\15\cdot T_B=60\Rightarrow T_B=(60)/(15)=4\\ \\T_A=12-T_B=12-4=8\\ \\R_A\cdot 8=360\Rightarrow R_A=(360)/(8)=45`

Hence,

`R_A-R_B+T_A-T_B=45-15+8-4=30+4=34`