Question

A 5.0 kg mass is added and the mass-spring system is turned horizontal. If the spring is displaced to - 2.0 cm, what is the potential energy of the mass-spring system when released just before it starts to move?

Answer 1

Potential energy of the spring mas system is, U = 0.06 Joules

Step-by-step explanation:

Given that,

Mass in spring mas system, m = 5 kg

Displacement in the spring, x = 2 cm = 0.02 m

Let the spring constant of the spring is 300 N/m.

We need to find the potential energy of the mass-spring system when released just before it starts to move. The energy stored in the spring is called its spring elastic energy. It is given by :

`U=(1)/(2)kx^2`

`U=(1)/(2)* 300* (0.02)^2`

U = 0.06 Joules

So, the potential energy of the mass-spring system when released just before it starts to move is 0.06 Joules. Hence, this is the required solution.