How many moles of BaCl2 are found in 8.62grams of BaCl2?

Question

asked Apr 20, 2021 132k views

2 Answers

Viktoriia · Answer 1 · 2021-04-21T09:46:44+0000

Answer: 0.04137 moles

Step-by-step explanation:

Ba = 137.327amu

Cl = 35.5

BaCl2 = 137.327 + (35.5*2)

BaCl2 = 137.327 + 71

BaCl2 = 208.327amu

1 mole of BaCl2 contains 208.327 g

x mole is present in 8.62g of BaCl2

x = 8.62 * 1 / 208.327

x = 0.04137g

Pymarco · Answer 2 · 2021-04-25T16:11:23+0000

Answer: 0.0416 moles BaCl2 or 4.16x10-2 moles BaCl2

Explanation: solution just multiply the given value 8.62g x 1mol BaCl2/207g which is the molar mass of barium chloride.