asked 148k views
0 votes
It takes 100,832 J of work to lift an elevator 18.3 meters. If this is done in 21.0 seconds, what is the average power of the elevator during the process? Explain your answer.

asked
User Sanja
by
7.5k points

1 Answer

4 votes

Answer:

4.80 kW

Step-by-step explanation:

Power = work / time

P = 100,832 J / 21.0 s

P ≈ 4800 W

answered
User Trinh
by
7.5k points