Question

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Answer 1

How many calories would be needed to evaporate half of a 300kg puddle of water?

90,000,000 Calories would be needed to evaporate half of a 300kg puddle of water.

Step-by-step explanation:

On average, 1 liter of water has a mass of 1 kg which requires 540,000 calories or
`2.3 * 10^6` Joules of energy to get evaporated when the temperature rises to 100 degrees. In the event that the water starts at a temperature T degrees, at that point an extra
`(100 - T) * 10^3` calories would be required to raise.

Since for 300kg of water we need 162000000 calories of energy .

Given:

1 kg = 540,000 calories or
`2.3 * 10^6`

300Kg =
`300 * 540000`

`= 162000000`

If half of the 300kg puddle has evaporate. Then
`(162000000)/(2)`

`= 81000000` calories of energy

So the evaporate value of 300kg puddle of water will be around 90000000 calories.